Write a Pythagorean Triplet whose one no. is 8. Step-by-step pleasee....
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Answered by
1
Step-by-step explanation:
This is Your Answer..
Pythagoras triplets are of the form.
2m, m-1 and m2+1.
It is given that smallest number is 8.
So, 2m= 8.
m=4.
Now, second number = m2 -1= 42 -1 15.
and, third number = m +1 4 +1 17.
Hence, the triplet is 8, 15 and 17.
Verification
172 82 + 152
289 64 +225
289 289.
Hence, proved.
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Answered by
3
Answer:
your answer is 6 ,8,10
Pythagorean triplets : √A^2 +B^2 =√C^2
Here
A is 6
B is 8
C Is 10
6^2=36
8^2=64
10^2=100
so...
√36+64=√100
your answer is 6;8;10
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