Question

write a pythagorean triplet whose one number is 6​

Answer 1

Answer:

8,10,6

Formula;if one number is given then the second number will be:

$\frac{n}{2} {}^{2} + 1$

Third number will be:

$\frac{n}{2} {}^{2} - 1$

Step-by-step explanation:

(6/2)²+1

(6/2)²-2

=3²+1

nd 3²-1

=9+1

nd 9-1

=10

nd 8