Derive the equation for maximum height for projectile motion.
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2as=vf^2_vi^2
As height is along y axis therefore
a=ay=_g
2(_g) H=vfy^2_viy^2
H=(0)^2_(vi sin theta)^2/_2g
H = vi^2 sin^2theta/2g
As height is along y axis therefore
a=ay=_g
2(_g) H=vfy^2_viy^2
H=(0)^2_(vi sin theta)^2/_2g
H = vi^2 sin^2theta/2g
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