Question

write a Pythagorean triplet whose one number is 8​

Answer 1

8

2

=64

⇒ 100−64=36

⇒

36

=6

⇒

100

=10

Let

Hypotenuse =10 [ Since its greater than 6 and 8 ]

Base =8 and

Perpendicular =6

(Hypotenuse)

2

=(Perpendicular)

2

+(Base)

2

[ Pythagoras theorem ]

⇒ (10)

2

=(6)

2

+(8)

2

⇒ 100=36+64

⇒ 100=100

∴ Pythagorean triplet are 6,8,10

Answer 2

This is the required answer.