Question

Write a Pythagorean triplet whose one of the members is (A)24(b)16(c)

Answer 1

${c}^{2} = {a}^{2} + {b}^{2}$

$c = \sqrt{ {24}^{2} + {16}^{2} }$

$c = \sqrt{576 + 256}$

$c = \sqrt{832}$

c = 28.84 (approx)

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Answer 2

Answer:

28.8444102037

Step-by-step explanation:

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