Question

Write a pythagorean
triplet whose smaller member is 6​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

AnswEr :

The Pythagorean triplet whose small number is 6 is 6,8,10.

ExplanaTion :

We know that the triplets of Pythagorean will be in the series,

$2m \: , \: ( {m}^{2} - 1) , \: ( {m}^{2} + 1)$

• Here, 2m is the smallest number.

There fore,

$2m \: = \: 6$

$m = \frac{6}{2}$

$m = \cancel \frac{6}{2}$

$m = 3$

Therefore, the value of m is 3.

Remaining two triplets are ...

$( {m}^{2} + 1) = {3}^{2} + 1$

${m}^{2} + 1 = 9 + 1$

${m}^{2} + 1 = 10$

=] the number is 10.

${m}^{2} - 1 = {3}^{2} - 1$

${m}^{2} - 1 = 9 - 1$

${m}^{2} - 1 = 8$

=] the number is 8.

The Pythagorean triplets in order are 6,8,10