Write a Pythagorean Triplet whose smallest member is 32.
Answers
Answered by
5
ANSWER
For any natural number n>1
2n,n
2
−1,n
2
+1 forms a pythagoras triplet.
Here,the smallest number is 2n
Given,
2n=6
=>n=3
∴ Other are
n
2
−1=3
2
−1
=9−1
=8
And,
n
2
+1=3
2
+1
=9+1
=10
Again,
2n=16
=>n=8
∴ Other are
n
2
−1=8
2
−1
=64−1
=63
And,
n
2
+1=8
2
+1
=64+1
=65
Hence, pythagorean triplet smallest number are (6,8,10),(16,63,65)
Answered by
7
Answer:
Smallest member=m
2m =32
m= 32/2
m=16
Other triplet numbers
m^2-1 = 16 ^2 -1
m =256-1 =255
m^2 +1 = 16^2 +1
m=256 +1 =257
SO ,THE PYTHAGOREAN TRIPLET ARE 32 ,255,257 ....
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