Math, asked by armaan77777, 9 months ago

Write a Pythagorean Triplet whose smallest member is 32.

Answers

Answered by narindervasudev
5

ANSWER

For any natural number n>1

2n,n  

2

−1,n  

2

+1 forms a pythagoras triplet.

Here,the smallest number is 2n

Given,

2n=6

=>n=3

∴ Other are

n  

2

−1=3  

2

−1

        =9−1

         =8

And,

n  

2

+1=3  

2

+1

         =9+1

         =10

Again,

2n=16

=>n=8

∴ Other are

n  

2

−1=8  

2

−1

        =64−1

         =63

And,

n  

2

+1=8  

2

+1

         =64+1

         =65

Hence, pythagorean triplet  smallest number are (6,8,10),(16,63,65)

Answered by Anonymous
7

Answer:

Smallest member=m

2m =32

m= 32/2

m=16

Other triplet numbers

m^2-1 = 16 ^2 -1

m =256-1 =255

m^2 +1 = 16^2 +1

m=256 +1 =257

SO ,THE PYTHAGOREAN TRIPLET ARE 32 ,255,257 ....

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