Question

Write a Pythagorean triplet whose smallest member is 8.​

Answer 1

Answer:

formula 2n,n²-1,n²+1

4×2,4×4-1,4×4+1

8,15,17 is the answer

Answer 2

Answer:

8, 15, 17

Step-by-step explanation:

$2m, m^2-1,m^2+1$ are Pythagorean triplets, where 2m is the smallest number and $m^2+1$ is the largest number.

According to Question,

2m = 8

=> m = 8/2 = 4

$m^2-1 = 4^2-1 = 16-1 = 15$

$m^2+1 = 4^2+1=16+1 = 17$