Math, asked by amirtha030507, 10 months ago

Write a Pythagorean triplet whose smallest number is 42.​

Answers

Answered by debasreeta
1

Answer:

2m=42

m=42/2

m=21

2m=21×2=42

m²+ 1= 21²+1=441+1=442

m²-1=21²-1=441-1=440

∴the numbers are 42,442 and 440

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Answered by KrinshaSolanki
0

Answer:

42,440 and 442

Explanation:

(42×42)+(440×440)=(442×442)

1764+193600=195364

Hence,proved.

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