Write a Pythagorean triplet whose smallest number is 42.
Answers
Answered by
1
Answer:
2m=42
m=42/2
m=21
2m=21×2=42
m²+ 1= 21²+1=441+1=442
m²-1=21²-1=441-1=440
∴the numbers are 42,442 and 440
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Answered by
0
Answer:
42,440 and 442
Explanation:
(42×42)+(440×440)=(442×442)
1764+193600=195364
Hence,proved.
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