write a pythagorean triplet whose smallest number is 8
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Answered by
0
Answer:
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Step-by-step explanation:
We get the Pythagorean triplets by using the General Formula that is [ 2m, m² - 1, n² + 1 ]
First let's take → m² - 1 = 8
→ m² = 8 + 1 = 9
→ m = 3
→ 2m = 6 and m² + 1 = 10
The triplet is therefore 6, 8, 10. hence, 8 is not the smallest method of this.
→ 2m = 8
→ m = 4
→ m² - 1 = 16 - 1 = 15 and
→ m² + 1 = 16 + 1 = 17
The triplet is 8, 18, 17 with 8 as the smallest number.
Answered by
1
Answer:
8 , 15 and 17
Step-by-step explanation:
8^2 + 15^2 = 17^2
64+ 225 = 289
289=289
hence proved
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