write a Pythagorean triplets whose number is
(a) 14
(b) 18
Answers
Answered by
0
Answer:
50
Step-by-step explanation:
14 can not be in the form of m²-1 or m²+1 as we get the following result. So,the three Pythagorean triplets are 14,48 and 50.
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Answered by
14
(a) 14, 48 and 50.
Step-by-step explanation.
We know that 2m, m² - 1, m² + 1 form a Pythagorean triplets.
→ 2m = 14.
→ m = 14/2.
→ m = 7.
→ m² - 1.
→ 7² - 1.
→ 48 - 1.
→ 47.
→ m² + 1.
→ 7² + 1.
→ 49 + 1.
→ 50.
(b) 9, 80 and 82.
→ 2m = 18.
→ m = 18/2.
→ m = 9.
→ m² - 1.
→ 9² - 1.
→ 81 - 1.
→ 80.
→ m² + 1.
→ 9² + 1.
→ 81 + 1.
→ 82.
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