Question

Write a python script that prints the first 10 cube numbers (x**3), starting with x=1 and ending with x=10.

Answer 1

Answer:

for i in range(1, 11):

i=i**3

print(i)

Explanation:

Answer 2

The python script that prints the first 10 cube numbers ($x^{3}$), starting with x=1 and ending with x=10 is:

cube_x = [ x ]

for number in range(1, 11):

cube = $number^{3}$

cube_x.append(cube)

for cube in cube_x:

print(cube)

start x = 1 ; end x=10.

The output will come as:

$1^{3} = 1, 2^{3} = 8, 3^{3} = 27, 4^{3} = 64, 5^{3} = 125, 6^{3} = 216, 7^{3} = 343, 8^{3} = 512, 9^{3} = 729, 10^{3} = 1000.$