Question

write a quadratic equation whose root are -4 and -5
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Answer 1

SOLUTION

TO DETERMINE

The quadratic equation whose root are -4 and -5

FORMULA TO BE IMPLEMENTED

The quadratic equation whose zeroes are given can be written as

$\sf{ {x}^{2} - (sum \:of \:the \: zeros)x + (product \:of \:the \: zeros) = 0}$

EVALUATION

Here it is given that a quadratic equation whose root are -4 and -5

The required Quadratic equation is

$\sf{ {x}^{2} - (sum \:of \:the \: zeros)x + (product \:of \:the \: zeros) = 0}$

$\implies \sf{ {x}^{2} - \big[ ( - 4) + ( - 5) \big]x+\big[ ( - 4) \times (- 5)\big] = 0}$

$\implies \sf{ {x}^{2} + 9x+20= 0}$

FINAL ANSWER

The quadratic equation whose root are -4 and -5 is

$\boxed{ \: \: \sf{ {x}^{2} + 9x+20= 0} \: \: }$

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ADDITIONAL INFORMATION

A general equation of quadratic equation is

$a {x}^{2} + bx + c = 0$

Now one of the way to solve this equation is by SRIDHAR ACHARYYA formula

For any quadratic equation

$a {x}^{2} + bx + c = 0$

The roots are given by

$\displaystyle \: x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac } }{2a}$

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LEARN MORE FROM BRAINLY

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