Question

Write a quadratic equation whose zeros are 3 and-6

Answer 1

Answer:

$x^{2} + 3x -18$ is the correct answer

Step-by-step explanation:

$\alpha = 3\\\beta = -6\\x^{2} - (\alpha +\beta)x+\alpha \beta \\x^{2}- -3x+-18\\x^{2} + 3x - 18$

HOPE IT HELPS !!