Write a quadratic polynomial.sum of whose zeroes is 2 and product -8 is -
Answers
Answered by
4
Answer:
p(x)=x^2-2x+8
because
We know that every quadratic equation is based on this relation..
p(x)=kx²−(α+β)x+αβ
where, α and β are the zeroes of given polynomial.
Now putting values of (α+β)=2 and αβ=−8 in above equation, we get ...
p(x)=x²−2x+8=0
Similar questions