Question

write a quadratic Polynomial sum of zeros is -3 and -8​

Answer 1

Required Answer:-

Given:

• Sum of zeros is -3.
• Product of zeros is -8.

To find:

• The quadratic polynomial.

Solution:

.Let α and β be the zeros of the polynomial.

Therefore,

➡ α + β = -3

➡ αβ = -8.

Therefore, the quadratic polynomial will be,

➡ x² - (α + β)x + (αβ) = 0

➡ x² + 3x - 8 = 0

Hence, the required quadratic polynomial will be,

➡ x² + 3x - 8 = 0

Answer:

• The required quadratic polynomial will be,
• x² + 3x - 8 = 0

Answer 2

Answer:

$\large\boxed{\fcolorbox{green} {black}{\color{yellow}{Required Answer}}}$

$\pink{Given}$

• Sum of zeroes is -3
• Product of zeroes is -8

$\pink{To \: Find}$

• The quadratic polynomial

$\pink{Solution}$

Let α and β be the zeroes of the polynomial

THEREFORE :

✍ α + β = -3

✍ α × β = -8

Therefore the quadratic equation will be :

$\implies{x}^{2} - (α + β)x + ( \alpha \beta ) = 0$

$\implies {x}^{2} + 3x - 8 = 0$

..............(Answer)

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Know more

Quadratic equation is any equation of the form

ax²+bx+c=0

This equation is valid only and only if a is not equal to zero.

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