Question

Write a quadratic polynomial , the sum and product of whose zeroes are 3 and -2 .​

Answer 1

Answer:

x² - 3x - 2

Step-by-step explanation:

Let the two zeroes of the polynomial be α and another one be β

They given that α + β = 3 ; αβ = -2

We know that,

p(x) = x² - (α + β)x + αβ

p(x) = x² - 3x + (-2) = x² - 3x - 2

Answer 2

Answer:

Quadratic polynomial ⇒ $x^{2}$ - 3x - 2

Step-by-step explanation:

The sum of the zeros are = ($\alpha +\beta$) = 3

The product of the zeros are = ($\alpha \beta$) = -2

Hence the required polynomial is,

           =k [ $x^{2}$ - ($\alpha +\beta$) x + $\alpha \beta$ ]

           =k [$x^{2}$ - 3x + (-2) ]

           =k [$x^{2}$ - 3x - 2 ]