Write a short note on cross bridge cycle(brief description)
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Hydrolysis of ATP to ADP and Pi, with products still covalently bonded to myosin, cause it to enter an energised state.
Cross bridge binds to actin. It undergoes a conformational change. ADP and Pi are released. You then get a power stroke (ie cross bridge moves, pulling actin along which causes the power stroke (ie the cross bridge moves pulling the actin along)
ATP binds to myosin, causing cross bridge to detach.
The process starts again.
Cross bridge binds to actin. It undergoes a conformational change. ADP and Pi are released. You then get a power stroke (ie cross bridge moves, pulling actin along which causes the power stroke (ie the cross bridge moves pulling the actin along)
ATP binds to myosin, causing cross bridge to detach.
The process starts again.
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this is answer of your question that u messaged me
magnetic dipole moment of a revolving electron
(1st)
-According to Neil Bohr's atom model, the negatively charged electron is revolving around a positively charged nucleus in a circular orbit of radius r.
The revolving electron in a closed path constitutes an electric current. The motion of the electron in anticlockwise direction produces conventional current in clockwise direction.
(2nd)
-picture as posted
(3rd)
-By substituting the values of e, h and m, the value of Bohr magneton is found to be 9.27 × 10–24 Am2
(4th)
In addition to the magnetic moment due to its orbital motion, the electron possesses magnetic moment due to its spin. Hence the resultant magnetic moment of an electron is the vector sum of its orbital magnetic moment and its spin magnetic moment.
*hope you may understand if not messages me
magnetic dipole moment of a revolving electron
(1st)
-According to Neil Bohr's atom model, the negatively charged electron is revolving around a positively charged nucleus in a circular orbit of radius r.
The revolving electron in a closed path constitutes an electric current. The motion of the electron in anticlockwise direction produces conventional current in clockwise direction.
(2nd)
-picture as posted
(3rd)
-By substituting the values of e, h and m, the value of Bohr magneton is found to be 9.27 × 10–24 Am2
(4th)
In addition to the magnetic moment due to its orbital motion, the electron possesses magnetic moment due to its spin. Hence the resultant magnetic moment of an electron is the vector sum of its orbital magnetic moment and its spin magnetic moment.
*hope you may understand if not messages me
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