Chemistry, asked by miniprash69, 10 months ago

Write a short note on Hoffmann elimination?

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Answered by nabafnazir5
19

Answer:

Hofmann elimination, also known as exhaustive methylation, is a process where a quaternary ammonium reacts to create a tertiary amine and an alkene by treatment with excess methyl iodide followed by treatment with silver oxide, water, and heat.


GurveerSaini: hyytg
miniprash69: ??
Answered by Anonymous
1

Answer:

The Hoffmann elimination is an organic reaction used to convert an amine with a B-hydrogen to an alkene using methyl iodide, silver oxide and water under thermal conditions The mechanism begins with an attack of the amine on methyl iodide to form an ammonium iodide salt.

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