write a simple program to accept a value from the user and display wheather it is even or odd
Answers
Answered by
0
Answer:
in python
n=int(input()
if n%2==0:
print("even number")
else:
print("odd")
Explanation:
Answered by
0
Answer:
Please repost this question with the coding language in which you want the answer...
Explanation:
By the way I can write this program in Python language :->
n=int(input("Enter a number"))
if (n%2) == 0:
print ("The number is even")
else:
print("The number is odd")
Hope it helps you
have a good day mate
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