Math, asked by yogeshm76, 10 months ago

Write all the formula of trignometery​

Answers

Answered by Anonymous
17

\huge\underline\mathfrak{Question-}

Write all the formulae of ttrignometery.

\huge\underline\mathfrak{Solution-}

Ratios :

  • Sinθ = \dfrac{Perpendicular}{Hypotenuse}

  • Cosθ = \dfrac{Base}{Hypotenuse}

  • Tanθ = \dfrac{Perpendicular}{Base}

  • Cosecθ = \dfrac{Hypotenuse}{Perpendicular}

  • Secθ = \dfrac{Hypotenuse}{Base}

  • Cotθ = \dfrac{Base}{Perpendicular}

\rule{200}1

Reciprocals :

  • Sinθ = \dfrac{1}{Cosecθ}

  • Cosθ = \dfrac{1}{Secθ}

  • Tanθ = \dfrac{1}{Cotθ}

  • Cosecθ = \dfrac{1}{Sinθ}

  • Secθ = \dfrac{1}{Cosθ}

  • Cotθ = \dfrac{1}{Tanθ}

  • Tanθ = \dfrac{Sinθ}{Cosθ}

  • Cotθ = \dfrac{Cosθ}{Sinθ}

\rule{200}1

Some identities :

  • Sin²θ + Cos²θ = 1

  • Sin²θ = 1 - Cos²θ

  • Cos²θ = 1 - Sin²θ

  • Cosec²θ - Cot²θ = 1

  • Cosec²θ = 1 + Cot²θ

  • Cot²θ = Cosec²θ - 1

  • Sec²θ - Tan²θ = 1

  • Sec²θ = 1 + Tan²θ

  • Tan²θ = Sec²θ - 1

\rule{200}1

Answered by Anonymous
3

✔Let's start

 \sin( \theta )  =  \frac{opposite \: side}{hypotenuse}

 \ \cos( \theta )  =  \frac{adjacent \: side}{hypotenuse}

 \tan( \theta)  =  \frac{opposite \: side}{adjacent \: side}

 \sec( \theta)  =  \frac{hypotenuse}{adjacent \: side}

 \csc( \theta)  =  \frac{opposite \: side}{hypotenuse}

 \cot( \theta)  =  \frac{adjacent \: side}{opposite \: side}

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