Question

Write all the four quantum number n,l,m, and s for last electron of chlorine ?​

Answer 1

Chlorine

Electronic configuration :

1s2 2s2 2p6 3s2 3p5

Quantum numbers for the differentiating electron/ the last electron :

n = 3 ( outermost / valence shell number )

l = 1 ( it varies as follows ... s subshell - 0, p subshell - 1, d subshell - 2, f subshell- 3 )

m = +1 ( -1 for Px, 0 for Py, +1 for Pz )

s = -1/2 ( it is +1/2 for the first electron in the degenerate orbital and -1/2 fir the second electron )

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