Question

write balanced equations:

Sodium carbonate on reaction with hydrochloric acid in equal molar concentrations gives sodium chloride and sodium hydrogen carbonate.

Sodium hydrogen carbonate on reaction with hydrochloric acid gives sodium chloride, water and liberates Co2.

Answer 1

ANSWER OF 1st QUESTION : Na2Co3+HCL--->Nacl+NaHCO3
ANSWER OF 2nd QUESTION : NaHCO3+HCL--->Nacl+H2O+CO2

Answer 2

Balanced equations:

The balanced equation for the reaction between sodium carbonate and hydrochloric acid with a equal concentrations results in production of sodium chloride and sodium hydrogen carbonate.

The reaction is given below:  

$\mathrm{Na}_{2} \mathrm{CO}_{3}(\mathrm{s})+\mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{NaCl}(\mathrm{aq})+\mathrm{NaHCO}_{3}(\mathrm{aq})$

The above given reaction is a "double displacement reaction".  

The balanced equation for sodium hydrogen carbonate on reaction with hydrochloric acid gives sodium chloride, water and liberates $CO_2$ is as shown:

$\bold{\mathrm{NaHCO}_{3}(\mathrm{S})+\mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{NaCl}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{CO}_{2}(\mathrm{g})}$.