Write chemical equation of the reaction of ehanoic acid with the following -(a)Na (b) Naoh (c) ch3ch2oh
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Ch3cooh+Na➡️ch3coona+1/2H2
Ch3cooh+NaOH➡️Ch3coona+h2o
Ch3cooh+ch3ch2oh ➡️ CH3COOCH2CH3 + h2o.
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