Question

Write chemical equation of the reaction of ethanoic acid with the following first sodium second Sodium Hydroxide third ethanol write the name of one main product of each reaction

Answer 1

1.) 2CH3COOH (aq.) + 2Na-----------> 2CH3COONa (aq.) + H2.....
It gives sodium ethanoate..

2.) CH3COOH (aq.) + NaOH------------->
CH3COONa (aq.) + H2O......
It gives sodium ethanoate n water

3.) CH3COOH (aq.) + HOC2H5 (l) --------->
CH3COOC2H5 (l) + H2O...
It gives out ester n water..

Hope it will helpful to u...

Answer 2

CH3COOH+Na = CH3COONa+ H2
(sodium ethanoate)


CH3COOH+ NaOH=CH3COONa+ H2O

CH3COOH+CH3CH2OH = CH3COOCH2CH3+ H2O (ethyl ethanoate)