Question

- write coofficient of x2in(x2-3) (x+2)​

Answer 1

Answer:

2

Step-by-step explanation:

Given : (x² - 3)(x + 2)

We can write this as :

→ x²(x + 2) - 3(x + 2)

→ x²(x) + x²(2) - 3(x) - 3(2)

→ x³ + 2x² - 3x - 6

On comparing this with ax³ + bx² + cx + d, we get

a = 1, b = 2, c = - 3, d = - 6

where, a = coefficient of x³

b = coefficient of x²

c = coefficient of x

d = constant

Hence, the coefficient of x² is 2.

• The above polynomial is cubic polynomial.
• A cubic polynomial is a polynomial of degree 3.

Answer 2

Given : (x² - 3)(x + 2)

To find out: write coofficient of x³

solutions:

Now ,

=>x²(x + 2) - 3(x + 2)

=> x²(x) + x²(2) - 3(x) - 3(2)

=> x³ + 2x² - 3x - 6

On comparing ( ax³ + bx² + cx + d=0), we found that

• a = 1
• b = 2
• c = - 3
• d = - 6

therefore, coefficient of x² is 2.