write cubes of 5 natural number which are of the form of 3n + 1 and verify the following statement that the cube of a natural number of the form 3n + 1 is a natural number of the same form .
Answers
Answered by
0
Step-by-step explanation:
4096 is expressed as 3n+1 where n=1365. So, here we expressed cubes of numbers 4,7,10,13,16 of form 3n+1 in the form of 3n+1. So, the statement “The cube of natural numbers of the form 3n+1 is a natural number of the form 3n+1.” is verified.
Similar questions