Math, asked by virendgupta5107, 8 months ago

write cubes of all natural number between 1 to 20 &verify the following statements
(1) cubes of all odd numbers are odd
(2)cubes of all even numbers are even​

Answers

Answered by TanishKuvar11
19

Answer:

1^3 = 1

2^3 = 8

3^3 = 27

4^3 = 64

5^3 = 125

6^3 = 216

7^3 = 343

8^3 = 512

9^3 = 729

10^3 = 1000

11^3 = 1331

12^3 = 1728

13^3 = 2197

14^ 3 = 2744

15 ^3 = 3375

16 ^3 = 4096

17^3 = 4913

18 ^3 = 5832

19^3 = 6859

20^3 = 8000

Cubes of odd nos are odd and even nos are even

Eg; 11 (odd no) -> 11x11x11 = 1331 (odd no)

18 (even no) -> 18x18x18 = 5832 (even no)

Hope this helps

Answered by bhoomikagowda08
11

Answer:

 {1}^{3}  = 1

 {2}^{3}  = 8

 {3}^{3}  = 27

 {4}^{3}  = 64

 {5}^{3}  = 125

  {6}^{3}  = 216

 {7}^{3}  = 343

 {8}^{3}  = 512

 {9}^{3}  = 729

 {10}^{3}  = 1000

 {11}^{3}  = 1331

 {12}^{3}  = 1728

  {13}^{3}  = 2197

 {14}^{3}  = 2744

 {15}^{3}  = 3375

 {16}^{3}  = 4096

 {17}^{3}  = 4913

 {18}^{3}  = 5832

 {19}^{3}  = 6859

 {20}^{3}  = 8000

This implies cubes of odd numbers are odd

cubes of even numbers are even

HOPE THIS HELPS YOU

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