Question

Write down an A.P sum of whose first 11 terms is zero. Pls explain step by step

Answer 1

Step-by-step explanation:

Let the AP of 11 term be

a-5d, a-4d, a-3d, a-2d, a-d, a, a+d, a+2d, a+3d, a+4d, a+5d

Sum of 11 term of AP is 0

a-5d + a-4d + a-3d + a-2d + a-d + a + a+d + a+2d + a+3d + a+4d + a+5d = 0

11a = 0

  a = 0

In the series a is 6th term

It will symmetry both sides.

So, the value of d would be any real number

Let d = 2

then AP will be,

-10, -8, -6, -4, -2, 0, 2, 4, 6, 8, 10