Write down an arithmetic sequence with common difference 4
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1
Answer:
simple take first term a= 1 and CD is = 4
Step-by-step explanation:
1,5,9,13............
Answered by
0
Common difference =yx.
4=yx.
y=x+4.
So the next term is x+4.
(b) Let x and x+4 be the two consecutive terms
of sequence such that sum of their reciprocals is 154.
x1+x+41=154.
x2+4x2x+4=154.
x=2−5 or x=6
then write step by step
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