Write down equation of the line perpendicular to 3 x + 8 y = 12 and passing through the point (-1,-2)
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Step-by-step explanation:
The equation of line perpendicular to 3x+8y=12 is
8x-3y=k
As the line passes through the point (-1,-2),
so 8(-1)-3(-2)=k
=> -8+6=k
=> k=-2
So the equation of line is 8x-3y=-2
or 8x-3y+2=0.
hope you got it.
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