Question

Write down the concentration of each of the following solutions in g/L and mol/L

3g Acetic acid in 100ml solution
​

Answer 1

Explanation:

3 g CH

3

COOH in 50 mL solution :

Concentration of CH

3

COOH in g L

−1

=

Volume of CH

3

COOH in L

Mass of CH

3

COOH in g

=

100

3×1000

=30 gL

−1

In terms of gram per litre :

3 g of CH

3

COOH in 100 mL has concentration = 30gL

−1

Molecular mass of CH

3

COOH=2×12+2×16+4×1=60

Molarity==

Volume of Solution in L

Mass of solute in moles

=

60×100

3×1000

=0.5mol L

−1

In terms of moles per litre:

3 g of CH

3

COOH in 100 mL has concentration = 0.5mol L

−1