Write down the β-decay equation and determine the maximum kinetic energy of the electrons emitted.Refer image for question and equation.
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The β decay equation of ²³Ne₁₀ is given by :
-β
²³Ne₁₀------------> ²³Na₁₁ + ⁰e₋₁ + v +Q
Mass defect can be given as :
Δm=m(²³Ne₁₀)- m(²³Na₁₁)
=22.994466-22.989770
=0.004696u
Q=Δmx931
=0.004696x931=4.372 Mev
The maximum kinetic energy of electron of emitted β particle is equal to Q value
=Ee=Q= 4.37 Mev
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