Question

Write down the equation of the perpendicular ti 3x+8y=12 and passing through the point (-1,-2)

Answer 1

Answer: 8x - 3y + 2 = 0

Step-by-step explanation:

line perpendicular to 3x + 8y = 12 is 8x - 3y = c, where c is a constant. Given this line passes through (-1, -2)

S0 (8x-1) - (3x-2) =c

-8 + 6 = c

c = -2

∴ the line is 8x - 3y = -2 or 8x - 3y + 2 = 0

Answer 2

Answer:

8X – 3Y = -2.

Step-by-step explanation:

Slope of line 3X + 8Y = 12 is -3/8. (Rewrite equation as Y = -3X/8 + 12/8 )

Since the new line is perpendicular to above line, the slope should be negative reciprocal. That is 8/3.

Equation of line with slope of 8/3 is  

Y = 8X/3 + C.

This line is passing through (-1, -2)  

 -2 = -8/3 + C

 C = 8/3 - 2 = 2/3

Hence the line equation is Y = 8X/3 + 2/3  

Simplifying 8X – 3Y = -2.