Physics, asked by vg499674, 5 months ago

Write down the law of friction. What will be the minimum value of velocity V, so that The object of mass

M will move in one complete rotation given that radius of circular path is ‘r’.​

Answers

Answered by soumyadevmukherjee11
1

Answer:

Any force or combination of forces can cause a centripetal or radial acceleration. Just a few examples are the tension in the rope on a tether ball, the force of Earth’s gravity on the Moon, friction between roller skates and a rink floor, a banked roadway’s force on a car, and forces on the tube of a spinning centrifuge.

Any net force causing uniform circular motion is called a centripetal force. The direction of a centripetal force is toward the center of curvature, the same as the direction of centripetal acceleration. According to Newton’s second law of motion, net force is mass times acceleration: net F = ma. For uniform circular motion, the acceleration is the centripetal acceleration—a = ac. Thus, the magnitude of centripetal force Fc is Fc = mac.

By using the expressions for centripetal acceleration ac from ac=v2r;ac=rω2ac=v2r;ac=rω2, we get two expressions for the centripetal force Fc in terms of mass, velocity, angular velocity, and radius of curvature:  Fc=mv2r;Fc=mrω2Fc=mv2r;Fc=mrω2.

You may use whichever expression for centripetal force is more convenient. Centripetal force Fc is always perpendicular to the path and pointing to the center of curvature, because ac is perpendicular to the velocity and pointing to the center of curvature.

Note that if you solve the first expression for r, you get r=mv2Fcr=mv2Fc.

This implies that for a given mass and velocity, a large centripetal force causes a small radius of curvature—that is, a tight curve.

Answered by rahikaamber2145
4

Answer:

hey there!

Explanation:

Whenever and object moves it's the friction that let it to rest at some distance.

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