Chemistry, asked by mickeysingh848, 6 months ago

Write down the percent composition of all elements in Ferric oxide?​

Answers

Answered by Abhishek9175
2

iron

Symbol :- Fe

Atomic Mass :- 55.845

# of Atoms :- 2

Mass Percent :- 69.943 %

oxygen

Symbol :- 0

Atomic Mass :- 15.9994

# of Atoms :- 3

Mass Percent :- 30.057 %

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Answered by TheValkyrie
1

Answer:

\bigstar{\bold{Percentage\:composition\:of\:Fe=70\%}}

\bigstar{\bold{Percentage\:composition\:of\:O=30\%}}

Explanation:

\Large{\underline{\underline{\bf{Given:}}}}

  • Compund is ferric oxide ( Fe₂O₃)

\Large{\underline{\underline{\bf{To\:Find:}}}}

  • Percentage composition of Fe and O in the compound

\Large{\underline{\underline{\bf{Solution:}}}}

→ Molar mass of Fe₂O₃ = 112 + 48 = 160 g

Percentage comosition of Fe:

Percentage composition of Fe = Molar mass of Fe in the compund/ Total molar mass of compound × 100

→ Molar mass of Fe = 56 g

→ Substitue the datas

  Percentage composition of Fe =( 56 × 2/160) × 100  = 70%

\boxed{\bold{Percentage\:composition\:of\:Fe=70\%}}

Percentage composition of O:

Percentage composition of O = Molar mass of O in the compund/ Total molar mass of compound × 100

→ Molar mass of O = 16 g

→ Substitute the datas,

   Percentage composition of O = ( 16 × 3/160) × 100

   Percentage composition of O = 30%

\boxed{\bold{Percentage\:composition\:of\:O=30\%}}

\Large{\underline{\underline{\bf{Notes:}}}}

→ Percentage composition of element = (Mass of element in compound/ Total mass of the compound) × 100

 

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