write down the values of n, l ,m for electron present in 3p
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Answer:
Basically: n is the shell number, which you indicated to be 3. l is the angular momentum quantum number, which is 0 for s, 1 for p (your case), 2 for d, 3 for f, 4 for g
hope it helps..!!
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In 3p, the values of n is 3; l is 1 and m is -1,0,+1
- for the 3p orbital:
- Principal quantum number (n) is 3.
- n-1, or 2 is the azimuthal quantum number (L)
- Magnum quantum number (M)=-L to +L
- The spin quantum no are +1/2 and -1/2.
- Principal quantum number for the 3p orbital is 3, azimuthal quantum number for the orbital is 1, magnetic quantum number for the orbital is 1, -1, and +1, and spin quantum number is +1/2 and -1/2.
- Principal quantum number, n, stands for the number of the shell, where n = 1, 2, 3, etc. L is a positive integer with values ranging from 0 to (n-1) that represents the sub-shell in which the electron is positioned.
- It is also known as an azimuthal or secondary quantum number. For a given l, the values of ml, which describes the spatial orientation of the orbitals, range from -l to +l. (with a gap of 1 between the two values). the spin is represented by ms.
- There are two alternative ms values, +1/2 and -1/2, for each value of ml. If clockwise spin is represented by +1/2, then anticlockwise spin is represented by -1/2.
- L = 0 denotes the s sub-shell, L = 1 the p sub-shell, L = 2 the d sub-shell, L = 3 the f sub-shell, and L = 4, the g sub-shell.
Hence, In 3p, the values of n is 3; l is 1 and m is -1,0,+1
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