Question

Write down values of n,l,m for electron present in 3p and 4d
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Answer 1

Explanation:

For electron present in 3p orbital,

n= 3, l = -1 to +1,

m = 2l + 1 = 2(-1) + 1 = -1 (When l= -1)

= 2(0) + 1 = 1 (When l= 0)

= 2(1) + 1 = 3 (When l= 1)

For electron present in 4d orbital,

n= 4, l = -2 to +2,

m = 2l + 1 = 2(-2) + 1 = -3 (When l = -2)

= 2(-1) + 1 = -1 (When l= -1)

= 2(0) + 1 = 1 (When l= 1)

=2(1) + 1 = 3 (When l= 1)

= 2(2) + 1 = 5 (When l= 2)