write equation for the formation of the following compound
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C(s) + 2 H2(g) → CH4(g)
The formation reaction for carbon dioxide (CO2) is
C(s) + O2(g) → CO2(g)
In both cases, one of the elements is a diatomic molecule because that is the standard state for that particular element. The formation reaction for H2O—
2 H2(g) + O2(g) → 2 H2O(ℓ)
—is not in a standard state because the coefficient on the product is 2; for a proper formation reaction, only one mole of product is formed. Thus, we have to divide all coefficients by 2:
H2(g) + 1/2 O2(g) → H2O(ℓ)
On a molecular scale, we are using half of an oxygen molecule, which may be problematic to visualize. However, on a molar level, it implies that we are reacting only half of a mole of oxygen molecules, which should be an easy concept for us to understand.
I hope it's help u mark it as brainlesit ⚛⚛
here is ur answer...
C(s) + 2 H2(g) → CH4(g)
The formation reaction for carbon dioxide (CO2) is
C(s) + O2(g) → CO2(g)
In both cases, one of the elements is a diatomic molecule because that is the standard state for that particular element. The formation reaction for H2O—
2 H2(g) + O2(g) → 2 H2O(ℓ)
—is not in a standard state because the coefficient on the product is 2; for a proper formation reaction, only one mole of product is formed. Thus, we have to divide all coefficients by 2:
H2(g) + 1/2 O2(g) → H2O(ℓ)
On a molecular scale, we are using half of an oxygen molecule, which may be problematic to visualize. However, on a molar level, it implies that we are reacting only half of a mole of oxygen molecules, which should be an easy concept for us to understand.
I hope it's help u mark it as brainlesit ⚛⚛
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