Question

Write equation for the reaction of Alcoholic KOH with:
2-Bromo-2-methyl propane​

Answer 1

Answer:

2 methyl prop-2-ene

Explanation:

Since KOH eliminates the halo group we have

CH3-C(Br)(CH3)-CH3  $\\\tt -KOH\rightarrow$ CH2=C(CH3)-CH3