Question

Write equation of solubility product for 1) BaSO4 2)CaF2. 3)Bi2S3

Answer 1

Answer:

1) The solubility product (Ksp) of BaSO4 is 1.5 × 10-9 . Calculate the solubility of barium sulphate in pure water and in 0.1M BaCl2 .

2). The solubility of calcium fluoride in saturated solution, it its solubility product is `3.2 xx 10.

3). K

sp

(Bi

2

S

3

)=[Bi

3+

]

2

[S

2−

]

3

=(2s)

2

×(3s)

3

=1.2×10

−98

K

sp

=108s

5

=1.2×10

−98

s

5

=

108

1.2

×10

−98

s

5

≃1×10

−100

Hence, s≃1×10

−20

.