Write euler's formula then and the number of faces in a solid if the number of vertices is 8 and number of edges is 12
Answers
Answer:
How much sugar(C12H22O11) will be required if each person on earth is given 100 molecules of sugar? (population of earth=3*10^10)
\orange{\underline{\textit{\green{\bf{CONCEPT \:used:-}}}}}
CONCEPT used:-
IS OF MOLE :-
\orange{\underline{\textit{\blue{\bf{DEFINITION:- }}}}}
DEFINITION:-
The mole (symbol: mol) is the unit of measurement for amount of substance in the International System of Units (SI). A mole of a substance or a mole of particles is defined as exactly 6.02214076×10^23 particles, which may be atoms, molecules, ions, or electrons.
\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}ANSWER
sugar(C12H22O11) required for each person on earth :-
GIVEN
100 MOLECULES TO BE GIVEN TO EACH PERSON
POPULATION OF EARTH-->3 \times {10}^{10}3×10
10
\orange{\underline{\textit{\green{\bf{TOTAL\: MOLECULES \:REQUIRED:-}}}}}
TOTALMOLECULES REQUIRED:-
PER PERSON REQUIREMENT× POPULATION OF EARTH --->
\begin{gathered}100 \: molecules \times 3 \times {10}^{10} \\ \\ 3 \times {10}^{12} = \: number \: of \: molecules \: required \: in \: total \: \end{gathered}
100molecules×3×10
10
3×10
12
=numberofmoleculesrequiredintotal
SO ONE MOLE OF SUGAR WEIGHT 342 grams
one mole = 6.022 \times {10}^{23} \: molecules \:6.022×10
23
molecules =342 grams
so one molecules weights -->
\frac{342}{6.022 \times {10}^{23} } \: grams
6.022×10
23
342
grams
so 3×10^12 molecules weights -->
\frac{342}{6.022 \times {10}^{23} } \times 3 \times {10}^{12} \: \: grams
6.022×10
23
342
×3×10
12
grams
\orange{\underline{\textit{\red{\bf{ REQUIRED\; WEIGHT}}}}}
REQUIREDWEIGHT
\underline{\blue{170 \times {10}^{ - 11} \: \: grams}}
170×10
−11
grams
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Euler's polyhedron formula, V−E+F=2
V = number of vertices = ?
E = number of edges = 21
F = number of faces = 16
V−21+16=2
V−5=2
V=7
Number of vertices = 7.