. Write expand :
a) (ab+bc) ²
b) (2x - 3y + 4)²
c) (3x-5y)³
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Step-by-step explanation:
Given, (ab+bc)2−2ab2c.
We know,
(a+b)2=a2+2ab+b2.
Then,
(ab+bc)2−2ab2c
=(ab)2+2(ab)(bc)+(bc)2−2ab2c
=a2b2+2ab2c+b2c2−2ab2c
=a2b2+b2c2.
2−3+4)(2−3+4)
2(2−3+4)−3(2−3+4)+4(2−3+4
Using the identity is (a+b)(a−b)=a2−b2.
Given: (3x−5y)(3x+5y) we apply the above identity by taking
a=3x and b=5y
We get, (3x−5y)(3x+5y)=(3x)2−(5y)2=9x2−25y2
Hence, (3x−5y)(3x+5y)=9x2−25y2.
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