Question

write expression describing the force acting on a body in terms of its momentum

Answer 1

as f =ma. also a =dv/dt . so f=mdv/dt .and mdv=dp . so, dp/dt =f
where dp =change in momentum
and dt change in time..
i hope it helps u..

Answer 2

Answer:

$\maltese\underline{\textsf{\textbf{AnsWer :}}}\:\maltese✠$

Let initial momentum ($p_i$) be mu

Let final momentum ($p_f$) be mv

According to 2nd law of motion

$\frac{p_f - p_i}{t} \propto \: f$

$\implies \: f \propto \frac{mv \: - mu}{t}$

$\implies \: f \propto \frac{m(v - u)}{t}$

$f \propto \: ma \: \: \: \: \: \: ( \frac{v - u}{t } = a )$

To remove the proportionality sign. We would add k as the proportionality constant

$f = kma \\ f = ma \:$

because by the definition of force k = 1

$\footnotesize \longrightarrow\: \underline{ \boxed{\sf Force \:= \: mass \times \: acceleration}}$