Chemistry, asked by tejaswinisonawale049, 1 day ago

Write expression for kc for the
Following chemical reaction.
1)2S02 (g) + 02 = 2S03 (g)
2) N204 (g) =2N02 (g)​

Answers

Answered by dipakdeore
1

(a) The expression for the equilibrium constant is Kc=[NOCl]2[NO]2[Cl2].

(b) The expression for the equilibrium constant is Kc=[NO2]4[O2].

(c) The expression for the equilibrium constant is Kc=[CH3COOC2H5][CH3COOH][C2H5OH].

(d) The expression for the equilibrium constant is Kc=[Fe3+][OH−]31.

(e) The expression for the equilibrium constant is Kc=[F2]5[IF5]2.

hope that was helpful for you

Answered by georgeanorue
1

Explanation:

In the first equation: The "2" that appears on SO3 is the number of moles of SO3 produced. Also the "2" that appears on SO2 is the number of moles of SO2 that is used in the reaction.

In the second equation: the '2' that appears on NO2 is also the number of moles of NO2 produced

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