write first 5 Terms of ap having common difference 6
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Answered by
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Step-by-step explanation:
first term of an AP , a = 6
common difference , d = 5
we know, general sequance of arithmetic progression is ; a , a + d, a + 2d, a + 3d....
so, A.P is ; 6, (6 + 5), (6 + 2 × 5), (6 + 3 × 5), .....
⇒AP is ; 6, 11, 16, 21, .....
general term, a_nan = a + (n - 1)d
= 6 + (n - 1)5
= 6 + 5n - 5
= 5n + 1
so, general term of given AP is (5n + 1), where n = 1, 2, 3, 4, 5, .....
you can verify it,
first term , a_1a1 = 5 × 1 + 1 = 6
2nd term , a_2a2 = 5 × 2 + 1 = 11
3rd term , a_3a3 = 5 × 3 + 1 = 16
fourth term, a_4a4 = 5 × 4 + 1 = 21
............
hence, AP is ; 6, 11, 16, 21....
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