Question

write first four terms of AP, when the first term a and the common difference D are given a follows:
1).a=10,. d=10 ​

Answer 1

Answer:

10 , 20 , 30 , 40

Note:

★ AP ( Arithmetic Progression ) : The sequence in which the difference between the consecutive terms are equal is called AP .

★ The nth term of an AP is given by ;

T(n) = a + (n-1)d , where a is the first term and d is the common difference of the AP .

★ The general form of an AP is given by ;

a , (a+d) , (a+2d) , (a+3d) , .... , [a + (n-1)d]

★ The common difference of an AP is given by ;

d = T(n) - T(n-1)

Solution:

Given : a = 10 , d = 10

To find : T(1) , T(2) , T(3) , T(4)

Now,

We know that ,

The nth term of an AP is given by ;

T(n) = a + (n-1)d

Thus,

1st term , T(1) = a + (1 - 1) d

= a

= 10

2nd term , T(2) = a + (2 - 1) d

= a + d

= 10 + 10

= 20

3rd term , T(3) = a + (3 - 1) d

= a + 2d

= 10 + 2•10

= 10 + 20

= 30

4th term , T(4) = a + (4 - 1) d

= a + 3d

= 10 + 3•10

= 10 + 30

= 40

Hence,

The first four terms of the AP are :

10 , 20 , 30 , 40 .

Answer 2

Answer:

if a=10,b=10,then ap:a1=a=10

a2=a+d=10+10=20

a3=a+2d=10+2(10)=30

a4=a+3d=10+3(10)=40

so,the AP:10,20,30,40......

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