Question

write first four terms of AP when the first term a and the common difference the are given as Follows (1) a=-2,d=0 (2) a=4,d=-3​

Answer 1

Step-by-step explanation:

(ii)Given: a = – 2, d = 0Let the series be a1, a2, a3, a4 …

a1 = a = -2

a2 = a1 + d = – 2 + 0 = – 2

a3 = a2 + d = – 2 + 0 = – 2

a4 = a3 + d = – 2 + 0 = – 2

 the series will be – 2, – 2, – 2, – 2 …

First four terms of this A.P. will be – 2, – 2, – 2 and – 2.

(iii) Given:a = 4, d = – 3Let the series be a1, a2, a3, a4 …

a1 = a = 4

a2 = a1 + d = 4 – 3 = 1

a3 = a2 + d = 1 – 3 = – 2

a4 = a3 + d = – 2 – 3 = – 5

 the series will be 4, 1, – 2 – 5 …

First four terms of this A.P. will be 4, 1, – 2 and – 5.

Answer 2

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$\color{red}\huge{\underline{\underline{\mathfrak{Question:-}}}}$

Write first four terms of AP when the first term a and the common difference the are given as Follows

(1) a=-2,d=0

(2) a=4,d=-3

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$\color{blue}\huge{\underline{\underline{\mathfrak{Answer}}}}$

First AP =2,2,2,2...and so on 

First AP =2,2,2,2...and so on  Second AP = 4,1,-2,-5......and so on  

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1) Given:-

• a=2
• d=0

${\blue{\bold{\text{Let the AP be }}}}$ a,(a+d),(a+2d) and so on.

${\blue{\bold{\text{Where a is first term and d is common difference}}}}$

${\blue{\bold{\text{Putting the value of a and d in the AP}}}}$

AP = 2,(2+0),(2+0+0),(2+0+0+0)........and so on

AP = 2,2,2,2,....... and so on.

2) Given:-

• a=4
• d=-3

${\blue{\bold{\text{Let the AP be}}}}$a,(a+d),(a+2d)......and so on.

${\blue{\bold{\text{Where a is the first term and d Is common difference}}}}$

${\blue{\bold{\text{Putting the value of a and d in the AP}}}}$

AP = 4,[4+(-3)],[4+2(-3),[4+3(-3)]......and so on.

AP = 4,(4-3),(4-6),(4-9)....... and so on

AP = 4,1,-2,-5

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Hope it helps