write first four terms of the A.P.,when the first term a and the common difference d are given as follows
1.a=10,d=10
2.a=-2,d=0
please solve both
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1. A=10 and d=10then
1st term =a=10
2nd term=a+d=10+10=20
3rd term= a+2d=10+2(10)=10+20=30
4th term =a+3d=+0+3(10)=10+30=40
So the 1st four terms are 10,20,30 ,40
2.a=2,d=0 then
1st term=a=2
2nd term=a+d=2+0=2
3rd term=a+2d=2+2(0)=2+0=2
4th term= a+3d=2+3(0)=2+0=2
So 1st four terms are2,2,2,2
1st term =a=10
2nd term=a+d=10+10=20
3rd term= a+2d=10+2(10)=10+20=30
4th term =a+3d=+0+3(10)=10+30=40
So the 1st four terms are 10,20,30 ,40
2.a=2,d=0 then
1st term=a=2
2nd term=a+d=2+0=2
3rd term=a+2d=2+2(0)=2+0=2
4th term= a+3d=2+3(0)=2+0=2
So 1st four terms are2,2,2,2
chkd:
the answers are in -
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1). 10,20,30,40.
2). 2,2,2,2 are the first four term of AP
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