write first term,and second term. 2:3
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Answer:
First term=2
Second term =3
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Step-by-step explanation:
the formula for finding the nth term is an AP is a (nth term ) = a+(n-1) d, where a is the first term and d is the common difference between any two consecutive term in the sequence.
Now, since the ratio between the 1 st and the 2 nd term is 2:3 ,we can write it as.
[a]/[a+(2-1)d]=2/3
[a]/[a+d]=2/3
Further solving this expression-
3[a] =2[a+d]
a=2d
now the ratio between the 3rd to fifth term can be written as -
[a+(3-1)d]/[a+(5-1)d]
= [a+2d]/[a+4d]
we know, from the above expression that a=2d so substituting a=2d:-
[a+2d]/[a+4d]
=[2d+2d]/[2d+4d]
=4d/6d
=2/3
therefore, the the ratio between the 3rd term and the 5 th terms ,AP is 2:3.
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